Question

Multiply.x²yx2 + 11x + 28y2+ 2x - 8хуStep 1Factor the denominator of the first fraction and the numerator of the second fraction.(x + 4)(x + 4) (x - 2)хбузI-2X ++4Step 2Multiply*?y4(x + 4)(x + 7)(x + 4)(x + 4 x - 2)xyD|)(x+4)=93Submit Skip (you cannot come back)

Answer 1

Given:

`(x^2y^4)/(x^2+11x+28)\cdot(x^2+2x-8)/(x^6y^3)`

Step 1

Factor the denominator of the first fraction and the numerator of the second fraction.

`\frac{x^2y^4}{(x+4)(x+7)^{}}\cdot(\mleft(x+4\mright)(x-2))/(x^6y^3)`

Step 2

Multiply

`\frac{x^2y^4}{\mleft(x+7\mright)(x+4)^{}}\cdot(\mleft(x+4\mright)(x-2))/(x^6y^3)=\frac{x^2y^4(x+4)(x-2)}{(x+7)(x+4)x^6y^3^{}}`