Given
![s(t)=16t^2](https://img.qammunity.org/2023/formulas/mathematics/college/a2z03p7pulfn7nx3nbfdt1f6yobdb14u3s.png)
Since the skydiver fell 4800ft, we need to set s(t)=4800 and solve for t, as shown below
![\begin{gathered} s(t)=4800 \\ \Rightarrow16t^2=4800 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wdv4hmht33egxfz74ehnrej23xlbpv2pxc.png)
Solve for t, as follows,
![\begin{gathered} \Rightarrow t^2=(4800)/(16)=300 \\ \Rightarrow t=\pm√(300)=\pm√(100*3)=\pm10√(3) \\ \Rightarrow t=\pm10√(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pvl8o9cobegyeyg9hhuqy7cuk4lkwvgtuo.png)
However, a negative time would indicate that the skydiver was falling before jumping from the plane, which is impossible.
Therefore, the only valid answer is 10sqrt(3).
The answer is 10sqrt(3)