When the ball is at height 31 cm it possess potential energy which is given as,
![U=\text{mgh}](https://img.qammunity.org/2023/formulas/physics/college/5ips10nj2eqessmvtpqshld4o7dtk78tiv.png)
When the ball rolls from height along the ruler the potential energy will be converted into kinetic energy.
According to conservation of energy,
![K=U](https://img.qammunity.org/2023/formulas/physics/college/b3cgwr8zelfq7fl4h27i15z9yzqziwtgxd.png)
Plug in the known expression,
![K=\text{mgh}](https://img.qammunity.org/2023/formulas/physics/college/rzalrzv52x5g8knk8eeb86eheiy2zlwr29.png)
Substitute the known values,
![\begin{gathered} K=(45.93\text{ g)(}\frac{1\text{ kg}}{1000\text{ g}})(9.8m/s^2)(31\text{ cm)(}\frac{1\text{ m}}{100\text{ cm}})(\frac{1\text{ J}}{1kgm^2s^(-2)}) \\ \approx0.140\text{ J} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/4b5wy90z0khjqhwkn22ti0je4wek36fk3s.png)
Thus, the kinetic energy of the ball is 0.140 J.