Question

Please help me am having a little bit of trouble

Answer 1

The expression we have is:

`7y^3-23+8y^2+(24/3)`

And we need to evaluate this expression when the value of y is:

`y=2`

Step 1. Substitute y=2 into every "y" that the expression has:

`7(2)^3-23+8(2)^2+(24/3)`

And now we can start solving the operations step by step.

Step 2. Solve the terms that have an exponent.

Since

`2^3=2*2*2=8`

And

`2^2=2*2=4`

The expression is now as follows:

`7(8)-23+8(4)^{}+(24/3)`

Step 3. The next step is to solve multiplications and divisions.

We start with the first multiplication 7(8) which is 56:

`56-23+8(4)^{}+(24/3)`

Step 4. Solve the next multiplication 8(4) which is 32:

`56-23+32^{}+(24/3)`

Step 5. Solve the division 24÷3 which results in 8:

`56-23+32^{}+8`

Step 6. Finally, solve all of the additions and subtractions:

`56-23+32^{}+8=73`

The result is 73, option D.

Answer:

D. 73