Question

Referring to the figures, find the area of the quadrilaterals shown.

Answer 1

Answer:

Step-by-step explanation:

The first figure shown is a trapezoid

Area of a trapezoid is given as:

`\text{Area = (}(a+b)/(2))h`

a = 10 ft

b = 4 ft

h = 5 ft

Substitute these values into the area formula

`\begin{gathered} \text{Area =}((10+4)/(2))*5 \\ \text{Area }=(14)/(2)*5 \\ \text{Area = }7\text{ }*\text{ 5} \\ \text{Area = 35 ft}^2 \end{gathered}`

The second quadrilateral is a parallelogram

Area = Base x Height

Base = 6 in

Height = 2 in

Substitute these values into the formula for the area of a parallelogram shown above:

Area = 6 x 2

Area = 12 in²