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solve the compound Inequalities, graph the solutions and write the solutions in interval notation
4x - 3 \leqslant 13 \: and \: - x - 5 \ \textless \ - 5

1 Answer

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Answer:

The solution is:


-10OR (-10,4)Explanation:<p>Given:</p>[tex]\begin{gathered} 4x-3\le13\ldots\ldots\ldots....\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots.(1) \\ -x-5<5\ldots\ldots\ldots\ldots\ldots........\ldots.\ldots\ldots\ldots\ldots\text{.}(2) \end{gathered}

From (2), we have:


x>-10\ldots\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots\text{.}(3)

Using this (1)


\begin{gathered} 4x\le16 \\ \\ x\le(16)/(4)=4\ldots\ldots\ldots\ldots.......\ldots\ldots\ldots\ldots\ldots\ldots\ldots..(4) \end{gathered}

The solution now is:

[tex]-10
User Manymanymore
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