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Find the sine of each acute angle in the triangle below. Select all that apply:- 40/41- 41/9- 41/40- 9/40- 9/41

Find the sine of each acute angle in the triangle below. Select all that apply:- 40/41- 41/9- 41/40- 9/40- 9/41-example-1
User Zaboco
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1 Answer

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The sine relation is given by the length of the opposite leg to the angle over the length of the hypotenuse.

Using the angle between the sides 9 and 41, we have:


\sin (\theta_1)=(40)/(41)

Using the angle between 40 and 41, we have:


\sin (\theta_2)=(9)/(41)

Therefore the correct options are the first and fifth ones.

User Arakweker
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