Question

A stuntman drives a car off of a parking garage. The car lands 68.38 meters away from the base of the garage. If the stuntman drove the car at 19 m/s, how tall is the parking garage?

Answer 1

Answer: 63.43 m

Step-by-step explanation:

Given

Car lands 68.38 m away from the base of the garage

Stuntman drove the car with speed
`u=19\ m/s`

Since there is no acceleration in the horizontal direction, so there is no change in velocity

`\Rightarrow 68.38=19* t\\\Rightarrow t=3.598\ s`

time taken to cover 68.38 m is 3.598 s

In this time car travels a vertical distance of h

Such that we can write

`\Rightarrow h=u_vt+(1)/(2)at^2\\\\\Rightarrow h=(1)/(2)gt^2\\\\\Rightarrow h=0.5* 9.8* (3.598)^2=63.43\ m`