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Solve the system of equations by elimination. 6x+4y=66x+2y=12

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Given the following system of equations:

6x+4y=6

6x+2y=12​

Let's determine the solution by Elimination:

6x + 4y = 6

- 6x + 2y = 12​

6x + 4y = 6

+ -6x - 2y = -12​

0 + 2y = -6

2y/-2 = -6/2

y = -3

Therefore, y = -3.

Let's determine x by substituting y = -3 in 6x + 4y = 6.

6x + 4y = 6

6x + 4(-3) = 6

6x - 12 = 6

6x = 6 + 12

6x = 18

6x/6 = 18/6

x = 3

In Summary:

The solution of the given system of equation is x=3 and y=-3 or (3,-3). We can also say that the graph of the two equations intersects at (3,-3).

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