Question

Find the equation for the line through points (-1,3) and (2,8) use y=Mx+b

Answer 1

Let's find the slope M using the following equation:

`\begin{gathered} M=(y2-y1)/(x2-x1) \\ \text{Where:} \\ x1=-1 \\ x2=2 \\ y1=3 \\ y2=8 \\ M=(8-3)/(2-(-1))=(5)/(3) \end{gathered}`

Now, let's use point slope equation:

`\begin{gathered} y-y1=M(x-x1) \\ y-3=(5)/(3)(x-(-1)) \\ y-3=(5)/(3)x+(5)/(3) \\ \text{Solving for y:} \\ y=(5)/(3)x+(5)/(3)+3 \\ y=(5)/(3)x+(14)/(3) \end{gathered}`