Given the two-way table, let's find the probability that a student selected at random is a junior student given that it's male.
Total number of students = 4 + 6 + 2 + 2 + 3+ 4 + 6 + 3 = 30
Number of male students = 4 + 6 + 2 + 2 = 14
Number of female students = 3 + 4 + 6 + 3 = 16
To find the probability that a randomly selected student is a junior given that the student is male, we have:
![P=\frac{Number\text{ of male }juniors}{\text{Number of male students}}](https://img.qammunity.org/2023/formulas/mathematics/college/iqs1bz4snyaanj1c7hkigyylu6h8ibgkjg.png)
Where:
Number of male junior students = 2
Number of male students = 14
Thus, we have:
![P=(2)/(14)=(1)/(7)](https://img.qammunity.org/2023/formulas/mathematics/college/rre15pjqgi50vbpgrkkw7fv2rl4liu8seb.png)
To write the probability as a percentage, multiply by 100:
![\begin{gathered} P=(1)/(7)\ast100 \\ \\ P=(100)/(7)=14.3\approx\text{ 14\%} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/f1hrt97w5xma3vh7kwkrc17fuywvn58dk3.png)
Therefore, the probability that a randomly selected student is a junior given that it's male is 14%
A