Question

Simplify the expression.3x 648x448OA. 18942 $3x2y2O B. 189272 3ry?Oc. 18x272 2xy2OD. 9327 32x32ResetNext

Answer 1

Given:

`3x\sqrt[3]{648x^4y^8}`

Solve:

`\begin{gathered} =3x\sqrt[3]{648x^4y^8} \\ =3x(27*8*3* x^3* x* y^6* y^2)^{(1)/(3)} \\ =3x(3^3*2^3*3* x^3* x* y^6* y^2)^{(1)/(3)} \\ =3x(3)^{(3)/(3)}(2)^{(3)/(3)}(x)^{(3)/(3)}(y)^{(6)/(3)}\sqrt[3]{3xy^2}^{} \\ =3x*3*2* x* y^2\sqrt[3]{3xy^2} \\ =18x^2y^2\sqrt[3]{3xy^2} \end{gathered}`