Question

Approximate value of the square root of 48 rounded to the nearest tenth.

Answer 1

Given

`\sqrt[]{48}`

This can be found as shown below:

`\begin{gathered} \sqrt[]{48} \\ =\sqrt[]{16*3} \\ =\sqrt[]{16}*\sqrt[]{3} \\ =4\sqrt[]{3} \end{gathered}`

Let us check for root 3 from the square root table

`\sqrt[]{3}=1.732`

Therefore,

`\begin{gathered} 4\sqrt[]{3} \\ =4*1.732 \\ =6.928 \\ \approx6.9(nearest\text{ tenth)} \end{gathered}`

Hence, the square root of 48 to the nearest tenth is 6.9