Question

When a piece of Samarium is taken out of the oven and cools from 230° to 152°, What isthe change in temperature?

Answer 1

We are asked to determine the change in temperature. To do that we will use the following formula:

`\Delta T=T_f-T_0`

Where:

`\begin{gathered} \Delta T=\text{ change in temperature} \\ T_f,T_0=\text{ final and initial temperature} \end{gathered}`

Now, we substitute the values:

`\Delta T=152-230`

Solving the operations:

`\Delta T=-78`

Therefore, the change in temperature is -78°