We have a square
![EF=10\sqrt[]{2}](https://img.qammunity.org/2023/formulas/mathematics/college/5qcaqvmemaxzqe736qlginrmbnz7e10mf4.png)
we can use the Pythagorean theorem in order to find y
![3y+11=\sqrt[]{(10\sqrt[]{2})^2+(10\sqrt[]{2})^2}=20](https://img.qammunity.org/2023/formulas/mathematics/college/6h43w98e02vxunpia5ks0j6byktzxcypon.png)
then we clear y

In order to find x, we need to remember the interior angles of a square are equals to 90° and the diagonals divided this angle into equal angles in other words the value is 45°
so we have the next equation


the value of x=10