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ements Us Question 4 A 4 in. 65° В Find the area of the sector formed by Z(ABC) in 2 Question Help: 0 Video

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Since 65 is equal to 13pi/36, then the area is:


(4^2)((13\pi)/(36))((1)/(2))=8((13\pi)/(36))=(26\pi)/(9)=9.076in^2

User Sinan Baymammadli
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