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Find the reference number of the value of t and terminal point determined by t A. -7 pie/6B. -41 pie/4

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Solution

For this case we have the following terminal point:

a) -7pi/6

The reference angle is pi/6

The quadrant is II

The terminal point is:


(-\frac{\sqrt[]{3}}{2},(1)/(2))

b) -41 pi/4

The reference angle is pi/4

The quadrant is IV

The terminal point is:


(\frac{\sqrt[]{2}}{2},-\frac{\sqrt[]{2}}{2})

User Mkurz
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