Question

Find two consecutive odd interferes such that 107 more than the lesser is six times the greater. The lesser consecutive odd integer is __, and the greater consecutive odd integer is __

Answer 1

Step 1: We have two consecutive odd integers:

x = Lesser odd integer

x + 2 = Greater odd integer

Step 2: Let's write the equation to solve for x, this way:

107 more than the lesser is six times the greater

107 + x = 6 (x + 2)

107 + x = 6x + 12

Like terms:

x - 6x = 12 - 107

-5x = - 95

Dividing by -5 at both sides:

-5x/-5 = -95/-5

x = 19, therefore x + 2 = 19 + 2 = 21

Step 3: The correct answer is that the lesser consecutive odd integer is 19, and the greater consecutive odd integer is 21.