Question

ev viuenIn a certain Algebra 2 class of 26 students, 21 of them play basketball and 7 of themplay baseball. There are 2 students who play neither sport. What is the probabilitythat a student chosen randomly from the class plays both basketball and baseball?

Answer 1

P = 2/13

Step-by-step explanation:

2 students from 26 that play neither sport. So, 24 students play basketball or baseball because:

26 - 2 = 24

Then, 21 of them play basketball and 7 of them play baseball. It means that 21 added to 7 less the number of students who play both sports equals 24. So:

21 + 7 - x = 24

Where x is the number of students that play both sports.

Solving for x, we get:

28 - x = 24

x = 28 - 24

x = 4

It means that 4 students play both basketball and baseball.

Therefore, the probability that a student chosen randomly from the class plays both sports is:

`P=(4)/(26)=(2)/(13)=0.154`

Because 4 out of 26 students play both sports.

So, the answer is P = 2/13