When we do the distributive, in the correct way, we must find 60x² on the first term. Therefore, let's multiply the terms on all options and see which one does not result in 60x².
Let's do the letter A first, we have

When we do the distributive we would have

As we wanted, then the letter A is appropriate. If the letter A is appropriate, let's test letter B

As we expected.
For the letter C, we will have

Now the last one is the letter D.

That's not appropriate, the correct would be 60x², therefore, the inappropriate beginning is the letter D.