Question

A gas occupies 3.56 L at 2.00 atm. If the volume increases by 3.55 L what is the pressure in kPa?

Answer 1

Final pressure (P2) = 101.47 kPa

Step-by-step explanation

Given:

Initial volume (V1) = 3.56 L

Final volume (increased by 3.55) = 7.11 L

Initial pressure (P1) = 2.00 atm = 202.65 kPa (1 atm = 101.325 kPa)

Required: Final pressure in kPa

Solution:

Use Boyles Law to solve the problem

P1V1 = P2V2

P2 = P1V1/V2

P2 = (202.65 kPa x 3.56 L)/7.11 L

P2 = 101.47 kPa