Given A , B and C are collinear
AB : AC = 2/5
A = ( -3 , 6 )
B = ( n , q )
C = ( -3 , -4 )
Note : the x coordinates of A = x-coordinates of C = -3
As the three points are collinear
So, the x-coordinates of the point B = -3
so, n = -3
Now, we will find the y-coordinates of the point B
AB : AC = 2/5
So,
so, the y-coordinates of the point B = q = 2
so, n = -3 and q = 2
The ordered pair of B is ( -3 , 2 )