Question

14. Solve for x and y. b x+13 5Y Linesa.b, and care perpendicular bisectors

Answer 1

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

3x - 9 ===> A

x + 13 ===> C

5y ====> B

Step 02:

We must apply the properties of triangles.

x + 13 = 5y eq.1

3x - 9 = x + 13 eq.2

eq .2

3x - 9 = x + 13

3x + x = 13 + 9

4x = 22

x = 22/4 = 11 / 2

eq. 1

x + 13 = 5 y

`\begin{gathered} (11)/(2)+13=5y \\ (11+26)/(2)=5y \end{gathered}`
`\begin{gathered} (37)/(2\cdot5)=y \\ (37)/(10)=y \end{gathered}`

The answer is:

x = 11 / 2

y = 37 / 10