Answer:
stress = 16.9 MPa
Step-by-step explanation:
The stress in the cable can be calculated as:

Where F is the force and A is the area. So, the area can be calculated as:

Where r is the radius. Since the radius is half the diameter, the radius is 4.0 mm and the area will be equal to:
![\begin{gathered} A=3.14(4\operatorname{mm})^2 \\ A=50.24\operatorname{mm}^2 \end{gathered}]()
Then, replacing the force F by 850 N, and A by 50.24 mm², we get that the stress is equal to:

Therefore, the answer is 16.9 MPa