Question

A rectangle has an area of 6x2 - 12x. If the length is 2x, what is the width?

Answer 1

`W=3x-6`

Step-by-step explanation

We have that the area of the rectangle is:

`A=6x^2-12x`

and the length is:

`2x`

The area of a rectangle is given as:

`A=L\cdot W`

where L = length; W = width

This means that to find the width, we can divide the area by the length.

That is:

`W=(A)/(L)`

This implies that:

`\begin{gathered} W=(6x^2-12x)/(2x) \\ \Rightarrow W=(6x^2)/(2x)-(12x)/(2x) \\ W=3x-6 \end{gathered}`

That is the width of the rectangle.