Given the functions:
![f(x)=x^2+17x+72](https://img.qammunity.org/2023/formulas/mathematics/high-school/s5709ii906ql2jg8aw4c5kss99lukmux2y.png)
![g(x)=x+9](https://img.qammunity.org/2023/formulas/mathematics/college/cu1ppsnpowogx2omx8458ui3dapxe1tfj9.png)
You have to subtract the functions:
![f(x)-g(x)](https://img.qammunity.org/2023/formulas/mathematics/high-school/jcmm9vdcdyhvon0nvqd9rbqvq5t8s26fgm.png)
![(x^2+17x+72)-(x+9)](https://img.qammunity.org/2023/formulas/mathematics/high-school/z09exld3qev9pfpzq6z7td6c0kz6jkoidn.png)
Note that I wrote both functions in parentheses separated by the minus sign. For the seconf term, the minus sign is as if the parenthesis is being multiplied by -1, the sign of both x and 9 is inverted:
![x^2+17x+72-x-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/3pakdxec9zy9xdbfzx0w00lt5gibt9lg3i.png)
Order the like terms
![x^2+17x-x+72-9](https://img.qammunity.org/2023/formulas/mathematics/high-school/pziiqq7hy9shmkri8p9eyw3w6h01yuukor.png)
And simplify
![x^2+16x+63](https://img.qammunity.org/2023/formulas/mathematics/high-school/ab9ixjj12dq3kn6xg67rg32mfin6s5aok7.png)
So the result in standard form is
![f(x)-g(x)=x^2+16x+63](https://img.qammunity.org/2023/formulas/mathematics/high-school/n62zlieugjcl0ir7jz4iwmr5qr1w9gn60t.png)