Question

Hello, I need some assistance with this homework question please for precalculusHW Q42

Answer 1

`\begin{gathered} f(x)\text{ = x}^2\text{ -7x} \\ 0=x^2\text{ - 7x} \\ 0=x(x\text{ -}7) \\ \\ x=0 \\ x\text{ - 7 = 0} \\ x=7 \\ \\ So,\text{ the intercepts are 0 and 7} \end{gathered}`

The answer is A, and the values are 0 and 7.