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*I’m struggling with this calculus practice problem, I need it solved*

*I’m struggling with this calculus practice problem, I need it solved*-example-1

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Given the series:


40-10+2.5-0.625+...

You need to remember that a Geometric Series has a Common Ratio, which is the factor between the terms.

In this case, the series is geometric, because every term is found by multiplying the previous one by:


r=(r_2)/(r_1)=(-10)/(40)=-(1)/(4)

By definition, the sum of the first "n" terms of Geometric Series, can be calculated by using the following formula:


S_n=(a_1(1-r^n))/(1-r)

Where:

-The first term is:


a_1

- The number of terms is "n".

- And "r" is the Common Ratio. This must be:


r\\e1

In this case, you can identify that:


\begin{gathered} a_1=40 \\ \\ r=-(1)/(4) \\ \\ n=6 \end{gathered}

Therefore, substituting values into the formula and evaluating, you get:


\begin{gathered} S_6=\frac{40_{}(1-(-(1)/(4))^6)}{1-(-(1)/(4))} \\ \\ S_6=\frac{40_{}(1-(-(1)/(4))^6)}{1+(1)/(4)} \end{gathered}
S_6=(4095)/(128)

Hence, the answer is:


S_6=(4095)/(128)

User Juan Bosco
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