Question

A small amount of aluminum reacts with hydrochloric acid (HCl) to form hydrogen gas and aluminum chloride.If 15.0 grams of HCl are used how much AlCl3 will be produced?

Answer 1

`18.27\text{ g}`

Step-by-step explanation:

Here, we want to get the amount of aluminum chloride produced

We start by writing the equation of the reaction

We have this as:

`Al_((s))\text{ + 3HCl}_((aq))\text{ }\rightarrow\text{ AlCl}_(3(aq))\text{ + 1.5H}_(2(g))`

From the equation of reaction, 3 moles of HCl produced 1 mole of AlCl3

The above is the theoretical number of moles

Now, let us get the actual

We start by getting the number of moles of HCl

We can get that by dividing the mass of HCl given by its molar mass

The molar mass of HCl is 36.5 g/mol

Thus, we have the number of moles reacted as:

`(15)/(36.5)\text{ = 0.411 mole}`

The number of moles of aluminum chloride produced from this is one-third

Mathematically, we have that as:

`(0.411)/(3)\text{ = 0.137 mole}`

To get the mass of aluminum chloride produced, we have to multiply the number of moles by the molar mass of aluminum chloride

The molar mass of aluminum chloride is 133.34 g/mol

Thus, we have the mass as:

`0.137\text{ }*\text{ 133.34 = 18.27 g}`