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A jar contains 8 white, 10 blue, and 18 red marbles. If one marble is drawn at random from the jar, find theprobability that:

A jar contains 8 white, 10 blue, and 18 red marbles. If one marble is drawn at random-example-1
User Bruny
by
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1 Answer

7 votes

To solve this problem, you can use the following formula:


P(A)=\frac{outcome\text{ in A}}{total\text{ number of outcomes}}.

Now, for all the problems, the total number of outcomes is:


8+10+18=36.

Now, there are 8 white marbles and 10 blue marbles, therefore:


P(white\text{ or blue\rparen= }(8+10)/(36)=(18)/(36)=(1)/(2).

Analogously:


P(white\text{ or red\rparen=}(8+18)/(36)=(26)/(36)=(13)/(18).
P(blue\text{ or red\rparen=}(10+18)/(36)=(7)/(9).

Answer:

1.-


(1)/(2).

2.-


(13)/(18).

3.-


(7)/(9).

User Apratimankur
by
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