Question

Juan conducted a survey of 550 employees of a company about their favorite pastime. Of these, 169employees chose playing games, 233 employees chose swimming. Compare the probability of an employee'schoosing playing games to an employee's choosing swimming.O about 32% to about 44%O about 32% to about 42%O about 31% to about 42%O about 31 % to about 44%

Answer 1

Write out the given data from the question

`\begin{gathered} \text{Total employees=550} \\ E\text{mployes playing games =169} \\ \text{Employees for swimming=233} \end{gathered}`

The probabilty of an event is given by the formula

`\frac{\text{ Required outcome}}{Total\text{ outcome }}`

Let

The probabilty of Employing playing games be P(E)

The probabilty of Employing for swimming be P(F)

then

`\begin{gathered} P(E)=\frac{\text{Number of employ}ees\text{ playing games}}{Total\text{ number of employ}ees} \\ \\ \end{gathered}`

Where

Number of employees playing games =169

Total employees =550

Substituting the values, we have

`P(E)=(169)/(550)=0.3072`

Since the probability is in percentage, multiply by 100

`P(E)=0.3072*100=30.72`

Hence,

The probability of employees playing game at pastime is about 31%

Similarly,

`\begin{gathered} P(F)=\frac{\text{Number of swimming employ}ees}{Total\text{ employe}es} \\ \text{Where } \\ \text{Number of swimming employ}ees=233 \\ Total\text{ employe}es=550 \end{gathered}`

Substituting the values, we have

`P(F)=(233)/(500)=0.4236`

Since the probability is in percentages, We multiply by 100

Hence

`P(F)=0.4236*100=42.36`

Hence

The probabilty of the employes swimming at passtime is about 42%

Therefore

the probability of an employee's choosing playing games to an employee's choosing swimming is about 31% to about 42%

Answer; about 31% to about 42%(Third option)