Question

Hello there. I have a problem below I am not sure if I need to take an inverse of the values or plug in a negative into something I don't fully see here. I was able to get the first question properly answered with no problem, So here is the question:Let θ be the angle that the vector A⃗ makes with the +x-axis, measured counterclockwise from that axis. Find the angle θ for a vector that has the following components.Part APart completeAx= 4.20 m, Ay= -2.10 mExpress your answer in degrees.θ =333∘part B: a x = 3.60 m, A y= 1.60 mExpress your answer in degrees.θ =∘You have found the angle that A⃗ makes with the +x-axis, measured clockwise from that axis.You may need to review Determining the Angle of a Vector.No credit lost. Try again.Previous AnswersRequest AnswerPart CAx= -3.00 m , Ay= 2.00 mExpress your answer in degrees.θ =Finally, I AM BLIND!! I can't see pictures/graphs. So could a tutor just write down everything in the answer box please and thank you :).

Answer 1

B. 23.96°

C. 236.31°

Explanation:

To calculate the angle using the following formula:

`\theta=\tan ^(-1)\mleft((A_y)/(A_x)\mright)`

We calculate in each case:

B.

`\begin{gathered} \theta=\tan ^(-1)\mleft((1.60)/(3.60)\mright) \\ \theta=\tan ^(-1)(0.444) \\ \theta=23.96\text{\degree} \end{gathered}`

C.

`\begin{gathered} \theta=\tan ^(-1)\mleft((2.00)/(-3.00)\mright) \\ \theta=\tan ^(-1)(-0.66) \\ \theta=-33.69 \\ \theta=270-33.69 \\ \theta=236.31\text{\degree} \end{gathered}`