Question

Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth

Answer 1

`√(13)` units

Explanation:

The distance formula is
`d=√((x_2-x_1)^2+(y_2-y_1)^2)` where
`d` is the distance between points
`(x_1,y_1)` and
`(x_2,y_2)`. Let
`(x_1,y_1)\rightarrow(5,1)` and
`(x_2,y_2)\rightarrow(3,4)`, thus:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)\\\\d=√((3-5)^2+(4-1)^2)\\\\d=√((-2)^2+(3)^2)\\\\d=√(4+9)\\\\d=√(13)`

Therefore, the distance between points P(5,1) and Q(3,4) is
`√(13)` units.