Question

write the equation of the line that passes through the points (-1,-2) and (3,10) in point slope form and slope intercept form

Answer 1

With the points first, we will calculate the slope m

(-1,-2) =(x1,y1)

(3,10)=(x2,y2)

`m=(y_2-y_1)/(x_2-x_1)`

then we substitute the values

`m=(10+2)/(3+1)=(12)/(4)=3`

the slope is m=3

point-slope form

`y-y_1=m(x-x_1)`

then we substitute the values and we obtain this form

the point slope form is

`y+2=3(x+1)`

slope-intercept form

`y=mx+b`

we clear y of the point-slope form and we obtain the slope-intercept form

`\begin{gathered} y=3x+3-2 \\ y=3x+1 \end{gathered}`

the slope-intercept form is

y=3x+1