Question

How can I solve (6^-1)(4^-2)

Answer 1

`(6^(-1))(4^(-2))`

1. Use the next rule of oxponents to rewrite the expression:

`a^(-n)=(1)/(a^n)`
`=((1)/(6^1))((1)/(4^2))`

2. Solve each exponent:

`=((1)/(6))((1)/(16))`

3. Multiply the fractions:

`\begin{gathered} =(1*1)/(6*16) \\ \\ =(1)/(96) \end{gathered}`

Then the given product is equal to 1/96 (or 96^-1)