We are asked that which line is perpendicular to the following equation.
![3y+2x=12](https://img.qammunity.org/2023/formulas/mathematics/college/z1nx0kyexf0r95z53xvpdiaz40x25jnrcu.png)
First of all, we have to convert this equation into the slope-intercept form so that we can identify it's slope.
![\begin{gathered} 3y+2x=12 \\ 3y=-2x+12 \\ y=(-2x)/(3)+(12)/(3) \\ y=(-2x)/(3)+4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/o5r3egx3bkd7n16okzt5nm42le8iokym52.png)
Recall that the standard slope-intercept form is given by
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where m is the slope and b is the y-intercept.
So comparing the standard form with the above equation, we find that
![m_1=(-2)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/dghdwu42orf2rhrpscsz8chrwm4oj4oh58.png)
![b=4](https://img.qammunity.org/2023/formulas/mathematics/high-school/jqbjioup74un7uzvgylyhqztsylsjc0tr4.png)
Now recall that the slopes of two perpendicular lines are negative reciprocals of each other.
![m_1=-(1)/(m_2)](https://img.qammunity.org/2023/formulas/mathematics/college/4qv83ntgiq6ef6mdrf1mcjqzd45udgvi5w.png)
Therefore, the line perpendicular to the given equation will have a slope of
![m_2=(3)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/s2wkx5ta6ygrah5hovpj0sixd4uwr8quwc.png)
Finally, now we will check which given option has the exact above slope, that will be the correct equation.
Option A:
![\begin{gathered} 6x-4y=24 \\ -4y=-6x+24 \\ y=(6x)/(4)-(24)/(4) \\ y=(3)/(2)x-6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gg7lg4uqvd2wisfy7f6qr56sbczkdffnzq.png)
This is the equation we were looking for since it has the slope m = 3/2
Therefore, the correct option is A.
The line 6x - 4y = 24 is perpendicular to the line 3y + 2x = 12