Question

ellusA 16.9 kg monkey is swinging on a5.32 m long vine. At the bottom ofits swing, it is moving 11.3 m/s. Towhat height does it swing?(Unit = m)

Answer 1

Given data

*The given mass of the monkey is m = 16.9 kg

*The length of the vine is L = 5.32 m

*The given speed is v = 11.3 m/s

The formula for the height is given by the conservation of energy as

`\begin{gathered} U_k=U_p \\ (1)/(2)mv^2=\text{mgh} \\ h=(1)/(2g)* v^2 \end{gathered}`

*Here g is the acceleration due to the gravity

Substitute the values in the above expression as

`\begin{gathered} h=\frac{1}{2*\text{9}.8}*(11.3)^2 \\ =6.5\text{ m} \end{gathered}`