Question

Peterson picks a card from a standard 52 card deck. He records the card and places it back in the deck and then chooses a second card. What is the probability of choosing a Jack and then a 10 numbered card?4/1691/1691/131/26

Answer 1

To solve this question, since Peterson is placing the card back in the deck, we have to compute the probability of getting a Jack from a deck of cards, then the probability of getting a 10 numbered card from a deck of cards. The answer is the product of the probabilities.

The probability of getting a Jack, since there are 4 Jacks, is:

`(4)/(52)\text{.}`

The probability of getting a 10 numbered card, since there are 4 cards of this type, is:

`(4)/(52)\text{.}`

Therefore, the probability of choosing a Jack and then a 10 numbered card is:

`(4)/(52)*(4)/(52)=(1)/(169)\text{.}`

Answer: Second option.