1 Answer

Hogsolo · Answer 1 · 2023-04-08T04:21:39+0000

The expression is given as,

$fg^(-8)h^(84)\cdot f^0g^(-80)h^(86)$

Consider the law of exponents,

$x^m\cdot x^n=x^(m+n)$

Use the above law to simplify the given expression.

Take the terms with same bases together,

$(f\cdot f^0)\cdot(g^(-8)\cdot g^(-80))\cdot(h^(84)\cdot h^(86))$

Apply the law,

$\begin{gathered} =(f^(1+0))\cdot(g^{-8+(-80)_{}})\cdot(h^(84+86)) \\ =(f^1)\cdot(g^{-88_{}})\cdot(h^(170)) \\ =fg^(-88)h^(170) \end{gathered}$

Thus, the simplified form of the given expression (without any denominator is obtained as,

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