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If ABCD is dilated by afactor of1/3, thecoordinate of A' would be:

If ABCD is dilated by afactor of1/3, thecoordinate of A' would be:-example-1

1 Answer

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SOLUTION:

The coordinates of A are;


(-3,-3)

When this is dilated by a factor of 1/3, the new coordinates of A are;


A^(\prime)=(-1,-1)

User Ben Rollert
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