Question

Suppose that an ideal gas in a sealed metal container (so it has a fixed volume) has its temperature increased by a factor of 1.55x. By what factor would the pressure of the gas increase or decrease in the container?

Answer 1

In order to find the factor that the pressure will decrease or increase, we need to analyse the following equation:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

This equation means the relation PV/T is always constant, where P is the pressure, V is the volume and T is the temperature.

So, using the given information, we have:

`\begin{gathered} (P_1V)/(T_1)=(P_2V)/(T_2)\\ \\ (P_1)/(T)=(P_2)/(1.55T)\\ \\ P_1=(P_2)/(1.55)\\ \\ P_2=1.55P_1 \end{gathered}`

That means the pressure will increase by 1.55x.