87.9k views
1 vote
Which equation represents a line which is perpendicular to the line y = 5x – 1?

Which equation represents a line which is perpendicular to the line y = 5x – 1?-example-1

1 Answer

5 votes

Answer:

6x + y = -1

Step-by-step explanation:

The general slope-intercept form of the equation of a line is given as;


y=mx+b

where m = slope of the line

b = y-intercept

Given the below equation of a line;


y=(1)/(6)x-1

we can see that the slope of the line, m = 1/6 and the y-intercept, b = -1

Any line that will be perpendicular to the above line must have a negative reciprocal of its slope. So if the slope of the given line is 1/6, then the slope of the perpendicular line will be;


-(1)/(((1)/(6)))=-1\ast(6)/(1)=-6

So the slope of the perpendicular is -6, the equation of the line can then be written as;


\begin{gathered} y=-6x-1 \\ \end{gathered}

Looking at the given options in the question, we'll need to rewrite the above equation;

Let's add 6x to both sides of the equation, we'll have;


\begin{gathered} 6x+y=6x-6x-1 \\ 6x+y=-1 \end{gathered}

User Huckle
by
9.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories