Question

1 You randomly choose a number from 1 to 10. Find P(even or less than 5). 12 = (level 2)

Answer 1

prob(even or Less than 5)= prob(even) + prob(<5)= 5/10 + 4/10 = 9/10 =4/5

`\begin{gathered} Total\text{ outcome=\lbrack{}1,2,3,4,5,6,7,8,9,10\rbrack} \\ \text{Even}=\lbrack2,4,6,8,10\rbrack\text{ , so, Prob(Even)=}(\lbrack2,4,6,8,10\rbrack)/(\lbrack1,2,3,4,5,6,7,8,9,10\rbrack)=(5)/(10) \\ \text{Less than 5=\lbrack{}1,2,3,4\rbrack so, Prob(<5)=}(\lbrack1^(\prime)2^(\prime)3^(\prime)4\rbrack)/(1,2,3,4,5,6,7,8,9,10\rbrack)=(4)/(10) \end{gathered}`
`\text{Prob(even or <5)= prob(even) +prob(<5)=}(5)/(10)+(4)/(10)=(9)/(10)=(4)/(5)`