Question

Find the slope and y-intercept of the line and graph.y = -1/2(x) + 1

Answer 1

Given the equation of the line:

`\text{ y = -}(1)/(2)x\text{ + 1}`

The equation is in slope-intercept form, y = mx + b.

Where,

m = slope

b = y-intercept

Thus,

The slope of the line, m = -1/2

The y-intercept, b = 1

Graphing the equation, let's determine at least two points of the line.

Let's use conditions when x = 0 and y = 0,

Point 1: At x = 0,

y = -1/2(x) + 1

y = -1/2(0) + 1

y = 1

(0,1)

Point 2: At y = 0,

y = -1/2(x) + 1

0 = -1/2(x) + 1

1/2(x) = 1

1/2(x)(2) = (1)(2)

x = 2

(2,0)

We get,