ThePart A
Let "x" be the number of tents that can hold 4 people and "y" represent the number of tents that can hold 4 people.
They bought a total of 60 tents, you can write an expression for the total number of tents as follows:
![x+y=60](https://img.qammunity.org/2023/formulas/mathematics/high-school/qhee30sbm0w4vqmw24iltqo09dlyvexsae.png)
The group is of 202 people if each tent was filled to capacity and everyone had a place to sleep, you can express the number of people that slept in tents as follows:
![4x+2y=202](https://img.qammunity.org/2023/formulas/mathematics/high-school/dkmp2a1nkyg1okit9bb685d44inlnxahof.png)
These equations represent the system of equations.
Part B
Next, find the intercepts of both lines to be able to graph them:
-First equation:
y-intercept:
Replace the equation with x=0
![\begin{gathered} x+y=60 \\ 0+y=60 \\ y=60 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vp6pl0z2lsaxu0u0yr55r05uoay4fiog4i.png)
The coordinates are (0,60)
x-intercetpt:
Replace the equation with y=0
![\begin{gathered} x+y=60 \\ x+0=60 \\ x=60 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/19x67tka4u4ttrf8inucoivui9hczygs2m.png)
The coordinates are (60,0)
- Second equation:
y-intercept:
Replace the equation with x=0 and solve for y:
![\begin{gathered} 4x+2y=202 \\ 4\cdot0+2y=202 \\ 2y=202 \\ (2y)/(2)=(202)/(2) \\ y=101 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/m50yu0jycb3uq6c4hzvq7n9cgdd7dmdfa6.png)
The coordinates are (0,101)
x-intercept:
Replace the equation with y=0 and solve for x:
![\begin{gathered} 4x+2y=202 \\ 4x+2\cdot0=202 \\ 4x=202 \\ (4x)/(4)=(202)/(4) \\ x=50.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/xqiai817ql1jmmdzl082hrnnth9h8y8drw.png)
The coordinates are (50.0,)
Plot the 5 points and draw the lines:
Part C
The solution of the system is the point where both lines intersect, first, solve the equation system:
![\begin{gathered} x+y=60 \\ 4x+2y=202 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4ufquj73gu861afd6752rtj7j8p9j3voyc.png)
-Solve the first equation for y:
![\begin{gathered} x+y=60 \\ y=60-x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/kr70f998n3hbcqvtn7e6u1n3ckcjwhs8oc.png)
-Substitute the expression in the second equation
![4x+2(60-x)=202](https://img.qammunity.org/2023/formulas/mathematics/high-school/l9ph6ptsr0aw8y7nzmh2tmx5gi6tu8ypnz.png)
Distribute the multiplication on the parentheses term:
![\begin{gathered} 4x+2\cdot60+2\cdot(-x)=202 \\ 4x+120-2x=202 \\ 4x-2x+120=202 \\ 2x+120=202 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/gn82fl1ixekfig2t5z8zppih808r5f5ydy.png)
Subtract 120 to both sides of the equal sign
![\begin{gathered} 2x+120-120=202-120 \\ 2x=82 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1sjrd92n9c4zxytqsi8x1dajdpt0disj9c.png)
Divide both sides by 2
![\begin{gathered} (2x)/(2)=(82)/(2) \\ x=41 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/s3h3phab35wxrqg2cp965kew426j0lifx1.png)
- Replace the value of x in the expression obtained for y:
![\begin{gathered} y=60-x \\ y=60-41 \\ y=19 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ssoadxx2m7cd7ryodu2my3hqhmj9m7ewnc.png)
The solution of the equation system is (41,19)
Part D
The solution of the equation system is x= 41 and y= 19, this means that they took 41 tents that could hold 4 people and 19 tents that could hold 2 people.