Question

In the circle below BD = 172° and ACFind m/BXD.

Answer 1

Given:

`\begin{gathered} \hat{BD}=172\degree \\ \hat{AC}=56\degree \end{gathered}`

To determine the m
`m\angle BXD=(1)/(2)(\hat{BD}+\hat{AC})`We plug in what we know:

`\begin{gathered} \begin{equation*} m\angle BXD=(1)/(2)(\hat{BD}+\hat{AC}) \end{equation*} \\ m\angle BXD=(1)/(2)(172+56) \\ Calculate \\ m\angle BXD=114\degree \end{gathered}`

Therefore, the answer is:

`\begin{equation*} 114\degree \end{equation*}`