The perimeter P of the rectagle is
![P=2W+2H](https://img.qammunity.org/2023/formulas/mathematics/college/2v6lstn2f117wgqke0w1qe6v4lgw2ndbfw.png)
where W is the width and H the height.
By substituting the given values into the perimeter, we have
![20=2\cdot6+2\cdot H](https://img.qammunity.org/2023/formulas/mathematics/college/27xkc040g4aicuvrhbjnyyjcsx087ji9tk.png)
which is equal to
![20=12+2W](https://img.qammunity.org/2023/formulas/mathematics/college/8rj9sjhywaa7p9dpqzlgz0oksxwgnd8s6j.png)
and we need to isolate W. This can be obtained by moving +12 to the left hand side as -12. It yields,
![\begin{gathered} 20-12=2W \\ 8=2W \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9ucppvoyvr29xsh1h7q3y9w9wubhmf1hrc.png)
and finally, W is given by
![\begin{gathered} 2W=8 \\ W=(8)/(2) \\ W=4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4tt2tn5j84yots99vold0gcd4hwm3mk005.png)
That is, each of the remaining sides measure 4 cm