What is the electric potential energy of an arrangement of two charges, -14.88 μC and -23 μC, separated by 34.35 cm?

asked Jun 24, 2023 190k views

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$\begin{gathered} E=(kQq)/(r) \\ E=(8.98\cdot10^9\cdot14.88\cdot10^(-6)\cdot23\cdot10^(-6))/(.3435)=-8.95J \end{gathered}$

Erikas answered Jun 30, 2023

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