Question

Step 1 of 2: Reduce the rational expression to its lowest terms. y^2 + 6y/6yStep 2 of 2: Find the restricted values of Y, if any, for the given rational expression. y^2 + 6y/6y

Answer 1

`\begin{gathered} 1)\text{ }(y+6)/(6) \\ 2)\text{ y }\\e0 \end{gathered}`Step-by-step explanation:

Step 1 of 2:

`(y^2+6y)/(6y)`
`\begin{gathered} y^2+6y\text{ = y(y + 6)} \\ (y^2+6y)/(6y)=(y(y+6))/(6y) \end{gathered}`
`\begin{gathered} y\text{ is common to numerator and denominator. It will cancel out} \\ (y(y+6))/(y(6))=(y+6)/(6) \end{gathered}`
`\text{The lowest term = }(y+6)/(6)`

step 2 of 2:

`\begin{gathered} The\text{ denominator = 6y} \\ Rational\text{ }expressions\text{ are not equal to zero in the denominator} \end{gathered}`

So equating the denominator to zero will give the restricted values of y

`\begin{gathered} \text{equating the denominator to zero} \\ 6y\text{ = 0} \\ y\text{ = 0/6} \\ y\text{ = 0} \\ \end{gathered}`

This means y cannot be equal to zero

The restricted value of y = 0