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How much force (in N) is exerted on one side of an 14.8 cm by 21.0 cm sheet of paper by the atmosphere?

1 Answer

7 votes

Answer:

3149.181 N

Step-by-step explanation:

the force exerted by the atmosphere can be calculated as

F = PA

Where P is the atmospheric pressure and A is the area of the sheet of paper.

The atmospheric pressure is P = 101325 Pa

And the area is equal to

A = Length x Width

A = 0.148 m x 0.210 m

A = 0.03108 m²

Because 14.8 cm = 0.148 m and 21.0 cm = 0.210 m

Now, we can calculate the force as

F = (101325 Pa)(0.03108 m²)

F = 3149.181 N

So, the force exerted is 3149.181 N

User SuhasD
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